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Ipatiy [6.2K]
3 years ago
7

This person did something wrong and I do not know what it is :( Please help this is for points!

Mathematics
1 answer:
Inga [223]3 years ago
7 0

Answer:

It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.

Instead of \frac{KN}{K'N'}, it should be \frac{K'N'}{KN}. That would make it (4 - 2) / (8 - 4) = 2 / 4 = 1/2.

Hope this helps!

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Help ASAP pleasee!!!!
Aleks04 [339]

Answer:

243

Step-by-step explanation:

hope this helps!! god bless!! -Natalia

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Identify an equation in point-slope form for the line perpendicular to
Zigmanuir [339]

Answer:

perp. : 1/3= m

y + 8 = 1/3(x -4): answer is c

y + 24/3 = (1/3)x - 4/3

y = (1/3)x - 28/3

Step-by-step explanation:

answer is c

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3 years ago
Which of the following best explains the meaning of the equation?
Assoli18 [71]

Answer:

On a number line, negative five and positive five are the same distance from zero.

Step-by-step explanation:

3 0
2 years ago
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The figure is made from squares of different sizes.Find the area of A if the side of each of the two indentical smallest square
Temka [501]

Answer:

The area of square A is 256 cm²

Step-by-step explanation:

  • <em>The four sides of a square are equal in length</em>
  • <em>Area of a square = side × side</em>

In the given figure

∵ The sides of the square E = 2 cm each

∵ The sides of the square F = 2 cm each

∵ The side of square D is the sum of the sides of squares E and F

∴ The sides of the square D = 2 + 2 = 4 cm each

∵ The side of square C is the sum of the sides of squares E and D

∴ The sides of square C = 2 + 4 = 6 cm each

∵ The side of square B is the sum of the sides of squares C, E, and F

∴ The sides of square B = 6 + 2 + 2= 10 cm each

∵ The side of square A is the sum of the sides of squares B, F, and D

∴ The sides of square A = 10 + 2 + 4= 16 cm each

∵ Area of square A = side × side

∴ Area of square A = 16 × 16

∴ Area of square A = 256 cm²

∴ The area of square A is 256 cm²

3 0
2 years ago
In circle A below, chord BC and diameter DAE intersect at F. If arc CD = 46° and arc BE = 78°, what is m_BFE? D B А​
wel

Given:

Consider the below figure attached with this question.

In circle A below, chord BC and diameter DAE intersect at F.

The arc CD = 46° and arc BE = 78°.

To find:

The measure of angle BFE.

Solution:

According to intersecting chords theorem, if two chords intersect inside the circle then the angle on the intersection is the average of intercepted arcs.

Using intersecting chords theorem, we get

m\angle BFE=\dfrac{1}{2}(m(arcCD)+m(arcBE))

m\angle BFE=\dfrac{1}{2}(46^\circ+78^\circ)

m\angle BFE=\dfrac{1}{2}(124^\circ)

m\angle BFE=62^\circ

Therefore, the measure of angle BFE is 62°.

6 0
3 years ago
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