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just olya [345]
3 years ago
6

For brainiest:):):):)

Mathematics
1 answer:
forsale [732]3 years ago
4 0

Answer:

i cant see anything

Step-by-step explanation:

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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
Which of the following equation has both -6 and 6 as possible values of c.... C²=36, c³=216, or none of the above
erastova [34]

Answer: THe equation C²=36 can have both -6 and 6 as possible values since -6 squared is 36 and so is 6 squared

7 0
3 years ago
anyone want to join my remind if so code is random911 if you need help i will help or just join for fun just to talk...Oh and fr
Inessa05 [86]
Thanks for the points :) hope you’re having a good day
5 0
3 years ago
Read 2 more answers
Find a parametric representation of the solution set of the linear equation. (Enter your answer as a comma-separated list of equ
STALIN [3.7K]

Answer:

  x = s, y = t, z = 8 -s -t

Step-by-step explanation:

It can work reasonably well to let s and t represent any of a pair of the variables. In the answer above, we have used x=s, y=t.

You could get more elaborate if you want:

  x = 4-s, y = 4-t, z = s+t

8 0
3 years ago
Write a quadratic function in vertex form whose graph has the vertex
ELEN [110]

Answer:

y = \frac{1}{2}(x - 5)² - 2

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (5, - 2), thus

y = a(x - 5)² - 2

To find a substitute (7, 0) into the equation

0 = a(7 - 5)² - 2

0 = 4a - 2 ( add 2 to both sides )

2 = 4a ( divide both sides by 4 )

a = \frac{2}{4} = \frac{1}{2}

y = \frac{1}{2} (x - 5)² - 2 ← in vertex form

4 0
3 years ago
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