Can I have a little help on how to do this?
1 answer:
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Answer:
The correct answer is the sales tax charged is $5.61 for $66 dinner at 8.5% tax rate.
Step-by-step explanation:
Cost of the dinner is $22. Tax levied on it is $1.87
Let x% is the rate of tax in the city.
Therefore, x% of 22 = 1.87
⇒ x = 1.87 × = 8.5
Therefore 8.5% is the tax rate in the city on foods.
Now another dinner costs $66.
Tax levied on it at the same percentage is given by 8.5% of 66 = $5.61.
Thus $5.61 as sales tax would be charged for a $66 dinner.
Hello there!
The formula for finding the Circumference of a circle is the following expression:
2
r, or 2 * 3.14 * the radius.
We have the radius, 8.3, so we have all necessary information to solve this problem.
Replace r with 8.3 in the expression "2 * 3.14 * r";
2 * 3.14 * 8.3
2 * 3.14 = 6.28
6.28 * 8.3 = 52.124.
The Circumference of your circle is 52.124 ft.
I hope this helps!
The formula for finding the Circumference of a circle is the following expression:
2
We have the radius, 8.3, so we have all necessary information to solve this problem.
Replace r with 8.3 in the expression "2 * 3.14 * r";
2 * 3.14 * 8.3
2 * 3.14 = 6.28
6.28 * 8.3 = 52.124.
The Circumference of your circle is 52.124 ft.
I hope this helps!
Answer:
b. Between 0.05 and 0.1
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses to be tested
We need to conduct a hypothesis in order to determine if the true mean is 50000, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Compute the test statistic
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
We can replace in formula (1) the info given like this:
Now we need to find the degrees of freedom for the t distirbution given by:
What do you conclude? Use the p-value approach
Since is a two tailed test the p value would be:
So on this case the best answer would be:
b. Between 0.05 and 0.1