16 is the original distance her dance class was from home
Reduce the numbers with 3. Any expression divided by 1 remains the same.
Answer:
The other term is<u> (x-3)</u>
Step-by-step explanation:
The quadratic function is:

Factoring this function we will have:

Therefore, the other term is<u> (x-3).</u>
I hope it helps you!
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be

.
You're minimizing

subject to the constraint

. Note that

and

attain their extrema at the same values of

, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is

Take your partial derivatives and set them equal to 0:

Adding the first three equations together yields

and plugging this into the first three equations, you find a critical point at

.
The squared distance is then

, which means the shortest distance must be

.