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dolphi86 [110]
3 years ago
5

Can someone please help me with these math problems ASAP?! Thanks in advance! ;)

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

11) Here given Function,

f(x) = \sqrt{2x-11}

And, g(x) = -|0.1|x+5

For f(x) = g(x)

\sqrt{2x-11}=-|0.1|x+5

2x-11=(-|0.1|x+5)^2

2x-11=0.01x^2 - 10|0.1|x+25

2x=0.01x^2 - 10|0.1|x+25+11

2x=0.01x^2 - 10|0.1|x+36

0.01x^2 - 10|0.1|x - 2x+36=0

When we solve this equation,

We found,

 x = 12.5227 ≈ 12.53

Thus, the required solution is, x = 12.53

12) Here the height of rocket A in x second,

f(x) = -16x^2+74x+9

And, The height gain by the rocket B in x seconds,

g(x) = -16x^2+82x

If at x seconds both A and B gain the same height,

That is, f(x) = g(x)

⇒ -16x^2+74x+9= -16x^2+82x

⇒74x + 9 = 82x

⇒ 82x - 74x = 9

⇒ 8x = 9

⇒ x = 1.125 ≈ 1.13

Thus, the required solution is x = 1.13 seconds (approx)


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1. Make sure your answers and work is SHOWN please and steps are in order.
JulijaS [17]

Been a while since I've done synthetic division.

1a. Let's assume that's supposed to be an equals sign

p(x) = 2x⁴ - 3x³ - 6x² + 5x + 6

possible rational roots have factors of 6 in the numerator and of 2 in the denominator.  We'll only worry about negative numerators.

Factors of six: 1,2,3,6, and we don't forget -1,-2,-3,-6

Factors of 2: 1,2

Possible rational roots:

(dividing by 1:) 1,-1,2,-2,3,-3,6,-6

(dividing by 2:) 1/2, -1/2  (2/2=1 is a duplicate, don't have to repeat it), 3/2, -3/2

Possible rational roots: 1,-1,2,-2,3,-3,6,-6, 1/2, -1/2, 3/2, -3/2

Synthetic division, trying x=1,

   1 | 2  -3  -6  5  6

             2  -1  -7  -2

       2    -1  -7  -2  4

Got a remainder of 4, so 1 isn't a root;

Trying x=-1  

-1 | 2  -3  -6  5  6

         -2   5  1  -6

     2  -5  -1  6  0

Zero remainder, found a root, x=-1.  This division says

(2x⁴ - 3x³ - 6x² + 5x + 6) / (x + 1) = 2x³ - 5x² - x + 6

Same set of rational roots on the cubic, we continue with x=2

2 | 2 -5 -1 6

         4 -2 -6

    2  -1 -3 0

Another zero remainder, x=2 is a root.  We're left with 2x² - x - 3 = 0, which factors as

(2x - 3)(x + 1) = 0

That's a second factor of x+1.  Our final factorization is

2x⁴ - 3x³ - 6x² + 5x + 6 = (x + 1)²(x-2)(2x - 3)

Fourth degree with a positive leading coefficient so goes to +infinity at both ends.  Double zero at x=-1, so it's tangent there, just touching the x axis, then down through x=3/2 and up through x=2.  

I'll leave the actually sketching and the other two polynomials to you -- that took some time.

4 0
3 years ago
20 points pls help no links
aniked [119]

Answer:

(-15, 13)

Step-by-step explanation:

-3(8x + 9y = -3)

4( 6x + 7y = 1)

-24x - 27y = 9

24x + 28y = 4 (add both equations)

y = 13

6x + 7*13= 1

6x + 91= 1

6x = 1 -91

x = -91/6

x = -15

3 0
3 years ago
If f(x)=x^2+2x-4 and g(x)=3x+1 find f(g(x))=()x^2+()x+()
barxatty [35]

Answer:

9x^2+22x-2

Step-by-step explanation:

f(g(x))=(3x+1)^2+2(3x+1)-4

      =9x^2+16x+6x+2-4

     =9x^2+22x-2

 to find the soultion of mentioned question you have to put the value of g(x) into f(x) and then solve it like normal ...

6 0
3 years ago
Calculate the straight line distance between the points (-10, -7) and (-8,1).<br> G.2(B)
tia_tia [17]

Answer:

2√(17) or about 8.2462 units.

Step-by-step explanation:

We want to determine the distance between the two points (-10, -7) and (-8, 1).

We can use the distance formula. Recall that:

\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute and evaluate:

\displaystyle \begin{aligned} d &= \sqrt{((-10)-(-8))^2 + ((-7) - (1))^2} \\ \\ &=\sqrt{(-2)^2+(-8)^2} \\ \\ &= \sqrt{(4) + (64)} \\ \\ &= \sqrt{68}\\ \\ &= 2\sqrt{17}\end{aligned}

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.

4 0
2 years ago
Which is equivalent to 3v8
Tomtit [17]

Answer:

C.

Step-by-step explanation:

= \sqrt[3]{8}^{x}\\

= Since \sqrt[3]{} = ^{1/3}

= So, It becomes :

= 8^{\frac{x}{3}

4 0
3 years ago
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