<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Answer:
36/132
Step-by-step explanation:
36/132, .27, 27%...
Answer:
1.33 years.
Step-by-step explanation:




Hi there! Hopefully this helps!
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Answer: 14.
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First we calculate <u>3 to the power of 2</u> and get 9.
|
\/
9 + 9 -
= 14.
Now we add<u> 9 + 9</u> to get 18.
18 -
= 14.
Then, we<u> divide 8 by 2</u> to get 4.
18 - 4 = 14.
Then we subtract<u> 4 from 18</u> to get.....You guessed it,<u> 14</u>!