If you multiply 38*(-36) you would get -1368. And to convert that into a fraction it could be -1368/1, -13680/10, etc.
Answer: some perfect cubes are
8 (2^3)
27 (3^3)
64 (4^3)
there are many perfect cubes
maybe there is more to this question?
Step-by-step explanation:
A perfect cube of a number is a number that is equal to the number, multiplied by itself, three times. If x is a perfect cube of y, then x = y3. Therefore, if we take the cube root of a perfect cube, we get a natural number and not a fraction. Hence, 3√x = y. For example, 8 is a perfect cube because 3√8 = 2.
Answer:
The angle must be at 3.81°
Step-by-step explanation:
The horizontal distance of the shooting range is 60 yards
The height of the target is 12ft.
We'll have to convert the value of the height from ft to yards.
1 yards = 3 foot
X yards = 12ft
X = 4yards.
The height of the target is 4 yards.
Now, to find the angle at which the shooter makes with the zenith of the target(height), we'll have to use use SOHCAHTOA
To know which of the rules we'll follow, a pictorial illustration of the values will help
(See attached document for better illustration).
From the diagram, we can see we have values at both opposite and adjacent.
Opposite = 4
Adjacent = 60
Hence we can use Tanθ = opposite/ adjacent
Tanθ = 4 / 60
Tanθ = 0.067
θ = Tan⁻0.067
θ = 3.81°
The angle at which the rifle must be set to hit the target is 3.81°
3 or null, dude. im pretty sure. anything that can be divided by 9, can also be divided by 3. For ex.) 27/9 = 3 and 27/3 = 9.
you can't just throw a negative in the middle of a big number, that wouldn't make sense. so the answer is 3... pretty sure.
(sorry if it's wrong it's 3AM, im tired, but im trying my best to answer questions rn)
Answer:
(-15, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
x + 5y = 0
3y + 2x = -21
<u>Step 2: Rewrite Systems</u>
x + 5y = 0
- Subtract 5y on both sides: x = -5y
<u>Step 3: Redefine Systems</u>
x = -5y
3y + 2x = -21
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 3y + 2(-5y) = -21
- Multiply: 3y - 10y = -21
- Combine like terms: -7y = -21
- Isolate <em>y</em>: y = 3
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define equation: x + 5y = 0
- Substitute in <em>y</em>: x + 5(3) = 0
- Multiply: x + 15 = 0
- Isolate <em>x</em>: x = -15
