It appears that none of your option choices are correct,, are you sure you copied them right ? I will show you how to solve this and how I got my answer.
The first step for solving this is to add the numbers in the parenthesis.
3 × 11 × 2 - 14 ÷ 7
Divide -14 by 7.
3 × 11 × 2 - 2
Divide the first 3 numbers together.
66 - 2
Subtract the numbers together to get your final answer.
64
Let me know if you have any further questions.
:)
Answer:
1
Step-by-step explanation:
Any number divided by itself equals 1. So, 23 divided by 23 is 1.
Answer:
where is the figure?
Step-by-step explanation:
-x² + 8x - 6 = 0
x = <u>-(8) +/- √((8)² - 4(-1)(-6))</u>
2(-1)
x = <u>-8 +/- √(64 - 20)</u>
-2
x = <u>-8 +/- √(44)
</u> -2<u>
</u>x = <u>-8 +/- 2√(11)
</u> -2
x = <u>-8 + 2√(11)</u> x = <u>-8 - 2√(11)
</u> -2 -2<u>
</u>x = 4 - √(11) x = -8 + √(11)
Answer:
<h2>
3,654 different ways.</h2>
Step-by-step explanation:
If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).
Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.
29C3 = 29!/(29-3)!3!
29C3 = 29!/(26!)!3!
29C3 = 29*28*27*26!/26!3*2
29C3 = 29*28*27/6
29C3 = 3,654 different ways.
This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders
