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3 years ago

For a Saturday matinee, adult tickets cost $8.50 and kids under 12 pay only $7.00. If 80 tickets are sold for a total

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

30 adult tickets,
50 kids tickets

Step-by-step explanation:

Given

Cost of adult ticket = $8.50
Cost of kids ticket = $7.00
Number of tickets = 80
Total cost = $605

Let the adult ticket be a and kids be k

We got equations

a + k = 80
8.5a + 7k = 605

From the first equation we get

k = 80 -a

Substituting k in the second equation

8.5a + 7(80 - a) = 605
8.5a - 7a + 560= 605
1.5a = 45
a = 45/1.5
a = 30

Then finding k

k = 80 - 30 = 50

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2 years ago

Think of a number . Multiply by 6 and add 5 is 11.Frame an equation and solve .

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3 years ago

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3 years ago

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3 years ago

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Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

and

$x^2+23x-210=(x-7)(x+30)$

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

hope this helps

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3 years ago