$\begin{array}{cccc}{} & {Romanticism} & {Gothic} & {Total} & {Males} & {48} & {63} & {111}& {Females} & {59} & {62} & {121} & {Total} & {107} & {125} & {232} \ \end{array}$

Step-by-step explanation:

Given

Romanticism

$Male = 48$

$Female = 59$

Gothic

$Male = 63$

$Female = 62$

Required

Complete the table <em>(See attachment for complete question)</em>

The table can be represented as:

$\begin{array}{cccc}{} & {Romanticism} & {Gothic} & {Total} & {Males} & {48} & {63} & {111}& {Females} & {59} & {62} & {121} & {Total} & {107} & {125} & {232} \ \end{array}$

The "total" column represents the number of males and female sampled, respectively.

$Male = 48 + 63 = 111$

$Female = 59 + 62 = 121$

The "total" row represents the number of Romanticism and Gothic sampled, respectively.

$Romanticism = 48 + 59 = 107$

$Gothic = 63 + 62 = 125$

The overall sample is calculated by adding up the number of males and females or the number of Romanticism and Gothic

$Overall = Male + Female$

$Overall = 111 + 121 = 232$

$Overall = Romanticism + Gothic$

$Overall = 107 + 125 = 232$

7 0

2 years ago

The product of (3 − 4i) and____is 25.

LiRa [457]

$(3-4i)(a+bi)=25\qquad\text{use FOIL method}\\\\(3)(a)+(3bi)+(-4i)(a)+(-4i)(bi)=25+0i\\\\3a+3bi-4ai-4bi^2=25+0i\\\\3a+3bi-4ai-4b(-1)=25+0i\\\\3a+3bi-4ai+4b=25+0i\\\\(3a+4b)+(3b-4a)i=25+0i\\.\qquad\qquad\qquad\qquad\Downarrow\\\\3a+4b=25\ and\ 3b-4a=0\\\\3b-4a=0\qquad\text{add 4a to both sides}\\\\3b=4a\qquad\text{divide both sides by 3}\\\\b=\dfrac{4}{3}a\qquad\text{substitute it to the first equation}\\\\3a+4\left(\dfrac{4}{3}a\right)=25\\\\3a+\dfrac{16}{3}a=25\qquad\text{multiply both sides by 3}$

$9a+16a=75\\\\25a=75\qquad\text{divide both sides by 25}\\\\\boxed{a=3}\qquad\text{put the value of a to}\ b=\dfrac{4}{3}a:\\\\b=\dfrac{4}{3}(3)\\\\\boxed{b=4}\\\\Answer:\ \boxed{(3-4i)\underline{(3+4i)}=25}$

6 0

2 years ago

PLEASE HELP ASAP! BRAINLIEST FOR RIGHT/BEST ANSWER!

zzz [600]

The correct answer is b I’m pretty sure

7 0

2 years ago