The correct answer to this question is 0.34 or 34 percent. To solve this, use the formula P(nuts/chocolate) = P(chocolate and nuts)/P(chocolate) = 0.25/0.73 = 0.342. Round to the nearest tenth of a percent, the answer is 34 percent. This is <span>the probability that a dessert chosen at random contains nuts given that it contains chocolate. </span>Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
Answer:
Step-by-step explanation:
3x + 6 + 4x + 20 = 180
7x + 26 = 180
7x = 154
x = 22
mA= 3(22)+6 =66+6 = 72°
mB= 4(22)+20 = 88 + 20 = 108°
Answer:
I hope this would help you:)
X+9=11
x=11-9
x=2
Basically just isolate for x
Answer:
Step-by-step explanation: