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kherson [118]
2 years ago
11

Please help me with this!

Mathematics
2 answers:
s344n2d4d5 [400]2 years ago
8 0

Answer:

Step-by-step explanation:

nikdorinn [45]2 years ago
7 0

Answer:

a) The pattern in the left side of the table with the exponents is a linear pattern drcreasing by 1

b) The pattern in the right side of the table with the résults is an descending and ascending pattern that form a curve.

Step-by-step explanation:

Results of the table:

4^4=256

4^3=64

4^2=16

4^1=4

4^0=1

4^-1=4

4^-2=16

Reminder:

you can shift an exponential graph Left or Right by adding or subtracting to the x value inside the exponent. You can shift an exponential graph Up or Down by adding or subtracting after the base has been raised to the exponent.

What is a pattern table?

Pattern tables allow you to create complicated or irregular patterns of features or groups by letting you specify unique dimensions for each instance in the pattern through an editable table. ... You can also include pattern tables in family tables so a particular family instance can use a specified pattern table.

Linear Number Patterns

A linear number pattern is a sequence of numbers whose difference between all the terms is the same. When you count, the difference between each successive number is 1. You start with 1, then you add 1 to get 2. Then you add another 1 to get 3.

What's the pattern rule?

Pattern Rules.

A numerical pattern is a sequence of numbers that has been created based on a formula or rule called a pattern rule. ... When numbers in a pattern get larger as the sequence continues, they are in an ascending pattern. Ascending patterns often involve multiplication or addition.

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Maurinko [17]
\bf \cfrac{x^2-x-42}{x-6}\implies \cfrac{(x+7)\underline{(x-6)}}{\underline{x-6}}\implies x+7

so.. the left-hand-side does indeed simplify to x+7, so the equation does check out.

however, notice something, for the equation of x+7, when x = 6, we get (6) + 7 which is 13.

BUT for the rational, we get    \bf \cfrac{x^2-x-42}{x-6}\qquad \boxed{x=6}\implies \cfrac{x^2-x-42}{\boxed{6}-6}\implies \stackrel{und efined}{\cfrac{x^2-x-42}{0}}

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