Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Double of 50 is 100, so 28*100=2800, now half of the answer is 2800/2=1400
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
radius^2 = (3 * Volume) / (PI * height)
</span></span></span></span><span>radius^2 = (3 * 12) / (PI * 3)
radius^2 = (36)/ (</span><span>9.4247779608) </span><span>
radius^2 = </span>
<span>
<span>
<span>
3.8197186342
</span>
</span>
</span>
radius =
<span>
<span>
<span>
1.95</span></span></span>
Using it's concept, it is found that the graph has no horizontal asymptote.
<h3>What are the horizontal asymptotes of a function f(x)?</h3>
The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, we have that:
- The function is undefined for x < 0, hence
is undefined.
- For x > 0, the funciton goes to infinity, hence
.
Thus, the graph has no horizontal asymptote.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
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Complete question:
Dada a função exponencial abaixo, se x=1, qual valor de imagem? * a) 1 b) -2 c) 0 d) -1
The function in the image is f(x) = 3^x-1
Answer:
A) 1
Step-by-step explanation:
To solve the exponential function above given that x = 1;
Substitute x = 1 into the exponential function
If x = 1
f(x) = 3^(x - 1)
f(1) = 3^(1 - 1)
f(1) = 3^0
f(1) = 1