Could you give some information? The table would be really good, I’d be able to help you more efficiently. ☺️
Answer:
<h2>
b = -2</h2>
Step-by-step explanation:
The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.
m = 2
(4, 6) ⇒ x₀ = 4, y₀ = 6
So, the point-slope form of equation:
y - 6 = 2(x - 4)
Changing to the slope-intercept form of the equation of the line (y = mx + b, where m is the slope and b is the y-intercept of the line):
y - 6 = 2x - 8 {add 6 to both sides}
y = 2x - 2 ⇒ b = -2
Answer:
not possible.
Step-by-step explanation:
number of invitations luanne has to address after x days = 120-15x
number of invitations Darius has to address after x days = 120 + 15(7-x)
so, if the number of invitations should be the same for both of them,
we have to equate their number of invitations
120-15x = 120 + 15(7-x)
subtracting 120 from both the sides,
-15x = 15(7-x) = 105 -15x
adding we 15x on both sides, we wont find any solution for x.
so, this isnt possible or the question must be wrong.
Answer:
yes
Step-by-step explanation:
Answer:
D. AC ≅ DF
Step-by-step explanation:
According to the AAS Theorem, two triangles are considered congruent to each other when two angles and a mon-included side of one triangle are congruent to two corresponding angles and a corresponding non-included side of the other.
Thus, in the diagram given:
<A and <B in ∆ABC are congruent to corresponding angles <D and <E in ∆DEF.
The only condition left to be met before we can conclude that both triangles are congruent by the AAS Theorem is for a mon-included side AC to be congruent to corresponding non-included side DF.
So, AC ≅ DF is what is needed to make both triangles congruent.
