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Lady bird [3.3K]
3 years ago
6

Which of the following best describes the function shown below?

Mathematics
2 answers:
Tanzania [10]3 years ago
7 0
Quadratic because I feels what I feels
Andrei [34K]3 years ago
6 0

Answer: I need to see the picture of the work first to tell u

Step-by-step explanation:

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Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)
kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios  between two points (x1,f(x1)) and (x2,f(x2)) is

  • ARC = [f(x2)-f(x1)]/ (x2-x1)

<em>In case a)</em>

f(-1)= -5*(-1)-8=5-8= -3          f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

<em>In case b)</em>

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

<em>In case c)</em>

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0
3 years ago
0.029 g in Scientific notation
Kay [80]
0.029= 2.9 x 10 power of negative 2
4 0
3 years ago
What is the equation of the line?
Nostrana [21]

Answer:

y=1/2x+2

Step-by-step explanation:

8 0
3 years ago
6. Let f(x)=x-2 and g(x) = x^2. Find the value of (fog)(-1).<br> A. -1<br> B.9<br> C.3<br> D.-3
inna [77]

Answer:

<h2>The answer is option A</h2>

Step-by-step explanation:

f(x) = x - 2

g(x) = x²

In order to find (fog)(-1) we must first find (fog)(x)

To find (fog)(x) substitute the g(x) into f(x) that's for every x in f (x) replace it with

g (x).

That's

(fog)(x) = x² - 2

To find (fog)(-1) substitute the value of x that's - 1 into (fog)(x)

We have

(fog)(-1) = (-1)² - 2 = 1 - 2 = - 1

Hope this helps you

8 0
3 years ago
Which equation is equivalent to 5x – 4y = 8?
aalyn [17]

Answer:

you got it right

Step-by-step explanation:

you mathaway to get the answer

6 0
3 years ago
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