Question

What is the midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i

Answer 1

Answer:  2 + 4 i

Step-by-step explanation:

Hi, to solve this we have to apply the next expression:

(a1 +a2)/ 2 + (b1 +b2 )/2 i=

Where a is the real part, and b is the imaginary part (with i)

For example, for our case:

6 -2i , 6 is the real part (2) and -2 is the imaginary part (b)

Replacing with the values given

(6 -4) /2+ (-2 +6) /2 i = 2 + 4 i

Feel free to ask for more if needed or if you did not understand something.

Answer 2

Answer:

Midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i is:

1+2i

Step-by-step explanation:

The midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i is:

$\dfrac{6-2i-4+6i}{2} \\\\=\dfrac{2+4i}{2}\\ \\=1+2i$

Hence, midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i is:

1+2i