1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DedPeter [7]
3 years ago
12

Julie drew a picture of her rectangular garden,. In her picture,the length of her garden is 7/8 inches and the width is 3/4 inch

es. She thinks the area of her picture is 21/32 inches. do you agree or disagree with Julie ? JUSTIFY YOUR ANSWER.(Area=Length X Width)
Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

21/32 square inches.


Step-by-step explanation:

The area of a rectangle = length x width

The area of her picture = length x widht

= 7/8 x 3/4

= 21/32

The area of her picture is 21/32 square inches.

Yes, I agree the area of the picture is 21/32 square inches.

The area must be in square inches. So she need to specify it.

Thank you.

You might be interested in
Someone pls help 0xy + 32y
Thepotemich [5.8K]

Answer:

32y

Step-by-step explanation:

0xy=0

If you change x or y on any number, you will get 0: 5*0=0, 100*0=0

So, 0+32y = 32 y

7 0
3 years ago
Read 2 more answers
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
“Hunter tutors students in mathematics to earn
Anna007 [38]

Answer:

Step-by-step explanation:

4 0
3 years ago
Bonjour, vous pouvez m'aider pour mon devoir de maths Quelle la valeur exacte de la longueur d'un cercle de rayon 7 m
strojnjashka [21]

Answer:

english?

Step-by-step explanation:

3 0
3 years ago
A pilot can fly 2100 miles with the wind in the same time she can fly 1890 miles against the wind. If the speed of the wind is 2
Anna007 [38]

Answer:

475 mph

Step-by-step explanation:

Distance = rate × time

time = distance / rate

If x is the speed of the plane in still air:

2100 / (x + 25) = 1890 / (x − 25)

Cross multiply:

2100 (x − 25) = 1890 (x + 25)

Distribute and solve:

2100x − 52500 = 1890x + 47250

210x = 99750

x = 475

5 0
3 years ago
Other questions:
  • Find the measure of Angle 1
    5·2 answers
  • EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?
    10·2 answers
  • If you know the pythagorean theorem, then you can always find the distance between two points in the plane.
    11·2 answers
  • Kevin says the line P and m will eventually Intersect is Kevin correct
    7·1 answer
  • Point A is on a number line halfway between -17 and 5. Point B is halfway between point A and 0. What integer does the point B r
    9·1 answer
  • Answer the question below
    6·1 answer
  • Perform the indicated operation. 6/8 - 3/8
    14·1 answer
  • What is the sign of -1.69+(-1.69)
    13·1 answer
  • 52<br> 5 halves<br><br> −52<br> negative 5 halves<br><br> −25
    12·2 answers
  • True or False? A circle could be circumscribed about the quadrilateral below
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!