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4 years ago

Given sinx=4//5 and cosx=35 .

Mathematics

1 answer:

Maslowich4 years ago

5 0

Given : Sin x = 4/5 and Cos x = 35 = 35/1

tan x = $\frac{Sin x }{Cos x}$

tan x = $\frac{4/5 }{35/1}$

tan x = $\frac{4}{5}\div \frac{35}{1}$

During the division of fractions flip the 2nd fraction after division sign and change the middle division sign to multiplication

tan x = $\frac{4}{5}\times \frac{1}{35}$

tan x = $\frac{4\times 1}{5\times 35}$

tan x = $\frac{4}{175}$

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HELP URGENT BRAINLIEST

nadya68 [22]

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin (60^\circ)=\dfrac{h}{12}$

$\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}$

Multiply both sides by 12.

$\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12$

$6\sqrt{3}=h$

Therefore, the height of the triangle is $6\sqrt{3}$ cm.

3 0

3 years ago

Find the area of the rectangle with a length of (x^2-2) and a width of (2x^2-x+2)

Katyanochek1 [597]

Area=legnth times width

so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)

so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4

5 0

3 years ago

Read 2 more answers

Water flows into a tank according to the rate F of t equals the quotient of 6 plus t and the quantity 1 plus t, and at the same

diamong [38]

Answer:

Step-by-step explanation:

The complete question is

Water flows into a tank according to the rate F(t)= (t+6)/(1+t), and at the same time empties out at the rate E(t)= (ln(t+2))/(t+1), with both F(t) and E(t) measured in gallons per minute. How much water, to the nearest galllon, is in the tank at time t=10 minutes.

Let C(t) be the amount of water in the tank at time t. We now that the rate of change of the tank is given by

$\frac{dC}{dt}=[\tex]rate at which water flows in- rate at which water flows out. Then [tex]\frac{dC}{dt}=\frac{t+6}{t+1}-\frac{\ln(t+2)}{(t+1)}[\tex]so, the desired expression is obtained by integrating with respect to t. This leads us to [tex]C(t) = \int \frac{t+1}{t+1}+ \frac{5}{t+1} - \frac{\ln(t+2)}{(t+1)} dt=t+ 5 \ln (|t+1|)-\int \frac{\ln(t+2)}{(t+1)} dt +C$

Unfortunately, the integral $\int \frac{\ln(t+2)}{(t+1)} dt$ cannot be expressed using fundamental functions. So, the problem cannot have an specific function (if you are willing to know the complete answer, the integral of this function uses the polylogarithm function with n=2).

Since you want the exact amount of water at time, you need to give C a value, that is, you need to know an initial condition for the problem. This means, you need to know the amount of water in the tank at time 0

8 0

3 years ago

To get from the stone to the tree you must avoid walking through a pond. To avoid the pond, you must walk 34 yards north

AlexFokin [52]

Answer:

Rounded, 22 yards.

Step-by-step explanation:

The pythagorean theorem states: a^2 + b^2 = c^2

a = 34, squared = 1156

b = 41, squared = 1681

Add those to get 2837.

√2837 = 53.26, rounded.

34 + 41 = 75

75 - 53 = 22

22 yards is your answer.

7 0

3 years ago

What is 10th term in 3,8,13,18?

skad [1K]

3+5=8+5=13 so if you keep doing this you will get 48 which is the answer

5 0

3 years ago

﻿Given sinx=4//5 and cosx=35 .

Given sinx=4//5 and cosx=35 .