Given that,
KM bisects ∠LKJ.
m∠LKM = 4x + 12 and m∠MKJ = 6x - 6
To find,
The value of x.
Solution,
As KM bisects ∠LKJ. It would mean that,
m∠LKM = m∠MKJ
Putting the above values,
4x+12=6x-6
We can solve the above equations as follows :
4x-6x=-12-6
-2x=-18
x=9
Therefore, the value of x is equal to 9.
Answer:
288.333333333
Step-by-step explanation:
Me, personally am not great with math, but I can say you have to take $865 then take away $40 then decide how much they get apiece. to do that you must divide 865 from 3. afterwards you should take that number away from 865 remember that you are also taking away 40 then you have your final answer
Answer:
Let the additional weight that can be added be = x
Current weight of the bag = 38 pounds
Total weight can be = 50 pounds
The equation becomes:
38+x < or equal 50
x < or equal 50-38=12
Hence, a weight of 12 pounds cab be added to the current wight.
Answer:
x-intercept: x = -4/3
Step-by-step explanation:
x-intercept when y = 0
-6x + 0 = 8
so
-6x = 8
x = 8/-6
x = -4/3
Answer:
a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%
b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%
Step-by-step explanation:
We have to find
a) P(X>40)= 1- P(x=40)
Using the z statistic
Here
x= 40 mph
u= 44mph
σ= 3 mph
z=(40-44)/3=-1.33
From the z-table -1.67 = 0.9082
a) P(X>40)=
Probability exceeding the speed limit = 0.9082 = 90.82%
b) P(50<X<55)
Now
z1 = (50-44)/3 = 2
z2 = (55-44)/3= 3.67
Area for z>3.59 is almost equal to 1
From the z- table we get
P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)
= P(2 < z < 3.67)
= P(z<3.67) - P(z<2)
= 1 - 0.9772
= 0.0228
or 2.28%
