Answer:
3 - x ≥ 9
Step-by-step explanation:
At least in inequality means greater than or equal to (≥)
Difference in mathematics means subtraction
The difference between a number x and 3
3 - x
is at least nine
3 - x ≥ 9
The inequality for the sentence is
3 - x ≥ 9
Step 1
Anything divided by one gives itself.
\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−8 and
1
−8
=
48
−12
Step 2
Convert -8−8 to fraction -\frac{64}{8}−
8
64
.
\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−
8
64
and
1
−8
=
48
−12
Step 3
Compare \frac{1}{8}
8
1
and -\frac{64}{8}−
8
64
.
\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and
1
−8
=
48
−12
Step 4
Anything divided by one gives itself.
\text{false}\text{ and }-8=\frac{-12}{48}false and −8=
48
−12
Step 5
Reduce the fraction \frac{-12}{48}
48
−12
to lowest terms by extracting and canceling out 1212.
\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−
4
1
Step 6
Convert -8−8 to fraction -\frac{32}{4}−
4
32
.
\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −
4
32
=−
4
1
Step 7
Compare -\frac{32}{4}−
4
32
and -\frac{1}{4}−
4
1
.
\text{false}\text{ and }\text{false}false and false
Step 8
The conjunction of \text{false}false and \text{false}false is \text{false}false.
\text{false}false
Hint
Do the arithmetic.
Solution
\text{false}false
21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
subtract the area of the rectangle from the area of the triangle
