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3 years ago

Find (-14 -14 14 7 -7

Mathematics

1 answer:

ElenaW [278]3 years ago

3 0

Answer:

Step-by-step explanation:

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Find the slope of a line parallel to each given line y = 4/5x + 1

natta225 [31]

Answer:

the slope of the line is 4/5

Step-by-step explanation:

an equation parallel to that is y= 4/5 - 3

Slopes are the same = parallel

3 0

3 years ago

Read 2 more answers

After the fraction x plus 1 all over 2 minus the fraction x plus 2 all over 3 x have been combined using the least common denomi

RoseWind [281]

If I've read this correctly, it looks like this.

$\dfrac{(x + 1)}{2 - \dfrac{(x + 2)}{3x}}$

If that is correct, then the first step is to put the top part of the denominator over 3x

$\dfrac{(x + 1)}{\dfrac{6x - (x + 2)}{3x}} = \dfrac{(x + 1)}{\dfrac{5x -2}{3x}}$

The next part is to flip a three tier fraction. I'm afraid I have to show what happens. My latex is not that strong.

What you get is

$\dfrac{3x*(x + 1)}{(5x - 2)}$

This is just about your final answer. You could write it as

$\dfrac{3x^2 + 3x}{(5x - 2)}$

6 0

3 years ago

150% of 60 and small explanation

gogolik [260]

We can turn 150% into a decimal by moving our decimal point two places to the left, or 1.5. We then multiply 1.5 with 60 as the word "of" in math automatically tells us to do that.

We have our answer of 90.

7 0

4 years ago

Read 2 more answers

Y= -7x-2 y+ 3 = -7x + 1 ( 2,3) no solution an infinite number of solutions

Naya [18.7K]

Answer:

Infinite number of solutions.

Step-by-step explanation:

y = -7x - 2

y + 3 = -7x + 1

Subtract 3 from both sides:

y = -7x - 2

- this is the same as the first equation.

We can put any number of valid combinations of x and y into this equation.

So there are infinite solutions.

8 0

3 years ago

Find sin θ if cos θ = 4/7 and θ in quadrant IV. Give an exact answer.

11111nata11111 [884]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}\\\\
-------------------------------\\\\
cos(\theta)=\cfrac{4}{7}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}
\\\\\\
\textit{using the pythagorean theorem to get the opposite side or "b"}
\\\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\implies \pm\sqrt{7^2-4^2}=b
\\\\\\
\pm \sqrt{33}$

now, the square root gives us both +/- versions, which is it? well, we know the angle θ is in the IV quadrant, well, the sine is "b" is negative there, thus is the negative version then

thus $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(\theta)=\cfrac{-\sqrt{33}}{7}$

3 0

4 years ago