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Talja [164]
3 years ago
9

CAN YOU PLEASE HELP ASAP!?

Mathematics
2 answers:
qwelly [4]3 years ago
6 0

Answer:

The original price of apples was $1.21

Step-by-step explanation:

Given is :

In winters the price per pound of apples went up by $0.75.

Sam bought 3 pounds of apples at the new rate and spent $5.88.

So, let say the original price of the apples was = x

And the new price is x+0.75

We will form the relevant equation:

3x+3(0.75)=5.88

The original price becomes:

3x+2.25=5.88

3x=3.63

x=\frac{3.63}{3}

x = 1.21

Hence, the original price of apples was $1.21

MAVERICK [17]3 years ago
4 0

Apples went up 0.75 a lb

p is the start price so new price is p + 0.75

we buy 3 lbs

3 ( p+ 0.75) = 5.88

now solve

3p  + 2.25 = 5.88

     -2.25      -2.25

3p =  3.63

/3         /3  

p = 1.21 a lb


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Answer:

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8 0
3 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

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(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

8 0
3 years ago
Olivia and her three siblings bring a sack lunch to school each day, consisting of a bagel, an apple, a cookie, and a juice box.
pogonyaev

Answer:

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Step-by-step explanation:

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