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Talja [164]
3 years ago
9

CAN YOU PLEASE HELP ASAP!?

Mathematics
2 answers:
qwelly [4]3 years ago
6 0

Answer:

The original price of apples was $1.21

Step-by-step explanation:

Given is :

In winters the price per pound of apples went up by $0.75.

Sam bought 3 pounds of apples at the new rate and spent $5.88.

So, let say the original price of the apples was = x

And the new price is x+0.75

We will form the relevant equation:

3x+3(0.75)=5.88

The original price becomes:

3x+2.25=5.88

3x=3.63

x=\frac{3.63}{3}

x = 1.21

Hence, the original price of apples was $1.21

MAVERICK [17]3 years ago
4 0

Apples went up 0.75 a lb

p is the start price so new price is p + 0.75

we buy 3 lbs

3 ( p+ 0.75) = 5.88

now solve

3p  + 2.25 = 5.88

     -2.25      -2.25

3p =  3.63

/3         /3  

p = 1.21 a lb


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\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right) \ \textgreater \  \ln \left(6^x\right)=\ln \left(21\right)

\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \  \ln \left(6^x\right)=x\ln \left(6\right)

x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \  \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)}

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