Answer:
D. 75(5r+3d+4f) and 75(5r)+75(3d)+75(4f)
Answer: 3 quarters is equal to .75 and 2 dimes is equal to .20
So far we have .95 with 5 coins
2 nickels which is equal to .10
1 penny
8 coins = 1.06
Step-by-step explanation:
Answer:
B: 12.9
Step-by-step explanation:
If A B and C are the alternatives, the answer is B: 12.9
The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.
And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6
Any questions, comment.
The equation you can use to solve the problem is;
50/30 = 300/x
Next Cross Multiply
50x = 9000
x = 9000/50
x = 180
The building's shadow is 180 feet tall
Answer:
$2000 was invested at 5% and $5000 was invested at 8%.
Step-by-step explanation:
Assuming the interest is simple interest.
<u>Simple Interest Formula</u>
I = Prt
where:
- I = interest earned.
- P = principal invested.
- r = interest rate (in decimal form).
- t = time (in years).
Given:
- Total P = $7000
- P₁ = principal invested at 5%
- P₂ = principal invested at 8%
- Total interest = $500
- r₁ = 5% = 0.05
- r₂ = 8% = 0.08
- t = 1 year
Create two equations from the given information:


Rewrite Equation 1 to make P₁ the subject:

Substitute this into Equation 2 and solve for P₂:





Substitute the found value of P₂ into Equation 1 and solve for P₁:



$2000 was invested at 5% and $5000 was invested at 8%.
Learn more about simple interest here:
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