Answer:
Plan A last 0.75 hours or 45 minutes.
Plan B last 1.5 hours or 90 minutes.
Step-by-step explanation:
Let
be the number of hours that the plan A last, an
the number of hours of plan B. Then for the Wednesday you have:
![2a+3b=6](https://tex.z-dn.net/?f=2a%2B3b%3D6)
And for the Thursday is:
![6a+5b=12](https://tex.z-dn.net/?f=6a%2B5b%3D12)
Multiply the equation of Wednesday by -3:
![-6a-9b=-18](https://tex.z-dn.net/?f=-6a-9b%3D-18)
Using the method of addition using this last equation and the equation of Thursday
![-6a-9b=-18\\6a+5b=12\\--------\\-4b=-6\\b=\frac{-6}{-4}\\b=1.5 hours](https://tex.z-dn.net/?f=-6a-9b%3D-18%5C%5C6a%2B5b%3D12%5C%5C--------%5C%5C-4b%3D-6%5C%5Cb%3D%5Cfrac%7B-6%7D%7B-4%7D%5C%5Cb%3D1.5%20hours)
Replacing the value of
in one of the equations
![6a+5b=12\\6a+5(1.5)=12\\6a+7.5=12\\6a=12-7.5\\a=\frac{4.5}{6} \\a=0.75hours](https://tex.z-dn.net/?f=6a%2B5b%3D12%5C%5C6a%2B5%281.5%29%3D12%5C%5C6a%2B7.5%3D12%5C%5C6a%3D12-7.5%5C%5Ca%3D%5Cfrac%7B4.5%7D%7B6%7D%20%5C%5Ca%3D0.75hours)
with the exception of perfect squares, all square root of whole numbers are irrational, e.g. √5
how about this one:
2.34334333433334.... I am increasing the number of 3s each time, thus
creating a decimal which never ends and never repeats.
or
12.3456789101112131415.... can you see what I am doing?
will it ever end? will it ever repeat?
Answer:
77
Step-by-step explanation:
Answer:I would say 6 but I could be wrong.
Step-by-step explanation: