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natita [175]
3 years ago
7

Which is bigger 40% of 90 or 1/2 of 80

Mathematics
2 answers:
Nastasia [14]3 years ago
4 0


40 percent of 90 is smaller than 1/2 of 80

40% of 90= 40*90/ 100= 36

1/2 of 80= 80/2= 40

So 1/2 of 80 is bigger

Mazyrski [523]3 years ago
3 0
40%of  90 is 36  and 1/2 of 80 is 40 so  1/2 of 80 is bigger then 40% of 90
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What is the estimate for square root of 22
tigry1 [53]
<span>16=4²
25=5² 
</span>So that means the square root of 22 is between 4 and 5.
Square 4.5 
4.5² = 20.25 
<span>4.5 < √22 < 5
So the nearest whole number would be 5.
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Happy Holidays~
5 0
3 years ago
in Hanley's school, 0.723 of the students participated in an event. if there are 1000 students in Hanley School, how many partic
Ugo [173]
Answer:

723 students participated in the event

Explanations:

The total number of students in Hanley's school = 1000

0.723 of the students participated in an event

Number of students that participated in the event = 0.723 x 1000

Number of students that participated in the event = 723

4 0
1 year ago
I need to know the distance between points x and y
USPshnik [31]

Answer:

Step-by-step explanation:

Distance between two points P(x1,y1) and Q(x2,y2) is given by: d(P, Q) = √ (x2 − x1)2 + (y2 − y1)2 {Distance formula} 2. Distance of a point P(x, y) from the origin is given by d(0,P) = √ x2 + y2.

8 0
3 years ago
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
3 years ago
I need help with this and fast if possible
11Alexandr11 [23.1K]

Answer:

<em>The answer is Hence Proved</em>

Step-by-step explanation:

       Given that CB║ED ,  CB ≅ ED

       To prove Δ CBF ≅ Δ EDF

  •       CB ≅ ED   ( Given )

        This means that the length of CB is equal to ED

        As CB║ED The following conditions satisfies when a transversal cut

        two parallel lines

  •    ∠ EDF = ∠ FBC   ( Alternate interior points )
  •    ∠ DEF = ∠ FCB   ( Alternate interior points )

       ∴ Δ CBF ≅ Δ EDF    ( By ASA criterion)

        The Δ CBF is congruent to Δ EDF By ASA criterion .

    <em>    Hence proved </em>

6 0
3 years ago
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