Question

Calculate the ratios in the table using the side lengths that you recorded in Part C.

Answer 1

Answer:

The ratios are;

$\dfrac{BC}{AB} = \dfrac{3}{5}$

$\dfrac{AC}{AB} = \dfrac{4}{5}$

$\dfrac{BC}{AC} = \dfrac{3}{4}$

$\dfrac{DE}{AD} = \dfrac{3}{5}$

$\dfrac{AE}{AD} = \dfrac{4}{5}$

$\dfrac{DE}{AE} =\dfrac{3}{4}$

Step-by-step explanation:

Given that the lengths of the sides are;

$\overline {AB}$  = 20

$\overline {BC}$  = 12

$\overline {AC}$  = 16

$\overline {AD}$  = 10

$\overline {DE}$  = 6

$\overline {AE}$  = 8

The ratios are;

$\dfrac{Length \ opposite \ \angle A}{Hypothenus} = \dfrac{BC}{AB} = \dfrac{12}{20} = \dfrac{3}{5}$

$\dfrac{Length \ adjacent\ \angle A}{Hypothenus} = \dfrac{AC}{AB} = \dfrac{16}{20} = \dfrac{4}{5}$

$\dfrac{Length \ opposite \ \angle A}{Length \ adjacent \ \angle A} = \dfrac{BC}{AC} = \dfrac{12}{16} = \dfrac{3}{4}$

$\dfrac{Length \ opposite \ \angle A}{Hypothenus} = \dfrac{DE}{AD} = \dfrac{6}{10} = \dfrac{3}{5}$

$\dfrac{Length \ adjacent\ \angle A}{Hypothenus} = \dfrac{AE}{AD} = \dfrac{8}{10} = \dfrac{4}{5}$

$\dfrac{Length \ opposite \ \angle A}{Length \ adjacent \ \angle A} = \dfrac{DE}{AE} = \dfrac{6}{8} = \dfrac{3}{4}$