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IRISSAK [1]
3 years ago
14

I could use some help on this​

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

A

Step-by-step explanation:

The length of CD represents the distance between the points C and D. Counting the points between them, if we start from point D, we need to get through points 1, 2, and 3 to get to C. That is 3 units, or A

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In a class of 18 students, 5 have a brother and 11 have a sister. There are 5 students who do not have any siblings. What is the
Sphinxa [80]
I think the images should make sense. If not, just comment, I’ll be here. (It’s only letting me insert one image so I’ll have to exp this part) once you’ve filled the two way table in, you circle the two squares that Apple to the situation. In this case, which ones don’t have a brother? The top right and bottom right fit that bill. Then you divide the number of students that actually have a sister but the two squares (added together) that do t have a brother. So it’d be 5/10 which is .5 for an answer

5 0
3 years ago
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Which function has zeros of -8, 1, and 3?
rodikova [14]

Answer:

the answer should be A

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
This question worth 38 points to whoever answers it :)
Paraphin [41]
Volumeprism=volumecube times number of cubes
vprism/vcube=number of cubes

vprism=12*5*4.25=255
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4 0
3 years ago
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Write a question that matches this equation.<br><br> 42 ÷ n = 6
Arlecino [84]
If we are supposed to give you like a life situation that matches the equation then I have one:
You have 42 watermelons and you need to divide them into equal groups. Let n equal the number of watermelons in each group. There are 6 groups in total. How many watermelons are in each group? (solve for n).

If this is not what you were looking for then my apologies.
5 0
4 years ago
Find the angle between the vectors u=i-9j and v=8i+5j
Katyanochek1 [597]

Answer: \cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}

Step-by-step explanation:

u \cdot v=(1)(8)+(-9)(5)=-37\\\\|u|=\sqrt{1^{2}+(-9)^{2}}=\sqrt{82}\\\\|v|=\sqrt{8^{2}+5^{2}}=\sqrt{89}\\\\\cos \theta=\frac{-37}{\sqrt{82}\sqrt{89}}\\\\\theta=\cos^{-1} \left(\frac{-37}{\sqrt{82}\sqrt{89}} \right)\\\\\theta=\boxed{\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}}

7 0
2 years ago
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