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3 years ago

What is -5(4x + 3) = -5x - 5 - 15x - 10?

Mathematics

2 answers:

Ber [7]3 years ago

7 0

Answer:

Step-by-step explanation:

-5(4x + 3) = -5x - 5 - 15x - 10

-5*4x - 5*3 = -5x - 5 - 15x - 10

-20x - 15 = -5x - 5 - 15x - 10

-20x + 5x + 15x = -5 -10 - 15

0= 0

inysia [295]3 years ago

7 0

Answer:

Infinite Solutions

Step-by-step explanation:

Firstly we distribute

-20x - 15 = -5x - 5 - 15x - 10

Collect like terms

-20x - 15 = -20x - 15

This represents infinite solution because they will result in 0.

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Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=

jasenka [17]

Answer:

The function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

$\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

The function is continuous at point x=36 if:

The function $\\ f(x)$ exists at x=36.
The limit on both sides of 36 exists.
The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

$\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}$

$\\ f(36) = \frac{36*6}{900} = \frac{6}{25}$

The limit of the $\\ f(x)$ is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

$\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Since

$\\ f(36) = \frac{6}{25}$

And

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Then, the function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

8 0

3 years ago

Find the value of x.<br><br> help

Komok [63]

Answer:

X=62

Step-by-step explanation:

X=62 because the side where x is and where the other degree is, they are congruent. And since you have to add 12 it would have to be 62 to be equal to 74.

7 0

3 years ago

A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessi

Elza [17]

Question:

A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders.

What is the number of seats occupied by concessionary ticket holders?.

Answer:

60 seats

Step-by-step explanation:

Given

Number of seats = 270