<em>f(d)=86,400·d</em>
if you set 1 day (d=1) you get f(1)=86,400 sec
if you set 1 day (d=2) you get f(2)=172,800 sec
...etc.
PART A
Coefficient
Coefficient h is 7.50
Coefficient s is 0.20
Variable
h and s
Constant
40
PART B
7.50h + 0.20s + 40
= 7.50(25) + 0.20(300) + 40
= 187.5 + 60 + 40
= 287.5
She earns $287.5
PART C
Yes, the coefficient of h would change to 9, the rests are still the same. Because she's no longer receive 7.50 per hour, and start earning 9 per hour, so the coefficient should change.
The expression would be
9h + 0.20s + 40
Answer:
$
Step-by-step explanation:
÷ 
= 
Hope this helps
I did im in algebra 1 now
