Question

The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine the length of the base, b, in meters. Then solve the equation.

Answer 1

Answer:

$\frac{(2)A}{h} =b$

b=0.00906m

Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of ​​any triangle is given by the following equation

$A=\frac{bh}{2}$

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of ​​a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

$A=\frac{bh}{2} \\\frac{2}{h} A=\frac{bh}{2} \frac{2}{h}$

$\frac{A(2)}{h} =b$

solving

$\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m$