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ANEK [815]
3 years ago
15

To check whether your writing is clear , you can

Computers and Technology
2 answers:
Rainbow [258]3 years ago
7 0

Answer:

you can use an app like Grammarly or you can perform some of this functions on your writing:

  • proof read your writing
  • check for wrong spelling
  • check for grammatical errors
  • check for proper use of multiple negatives
  • check for proper use of nouns, verbs and adjectives  

Explanation:

Writing is a way of expressing one intentions or ideas about something or somebody. it is very important to put good effort into writing a good piece free of too many errors so that your intended audience will understand what ideas or intentions you are trying to communicate across.

to check whether you writing is clear you can prof read check for wrong spellings, check for grammatical errors, check for proper use of multiple negatives, check fro proper use of nouns, verbs and proper use of parts of speech. All this can also be done using Mobile/web applications like Grammarly

Bezzdna [24]3 years ago
3 0

Answer: Hi!, hope this helps. :)

Explanation: After you proofread and do a first edit of you paper, you should either read it out loud or have someone read it back to you. Hearing the paper out loud is one of the best ways to find unclear wordings. You should also do revising. You should make sure your writing meets the requirements of the writing catagory and maybe even get a rubric of the requirements.

This is the best answer I can give, I hope this answers your question! Try to make me the brainliest if you can.

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Answer:

The function in Python is as follows:

def digitSum( n ):

if n == 0:

 return 0

if n>0:

    return (n % 10 + digitSum(int(n / 10)))

else:

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Explanation:

This defines the method

def digitSum( n ):

This returns 0 if the number is 0

<em> if n == 0: </em>

<em>  return 0 </em>

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<em> if n>0: </em>

<em>     return (n % 10 + digitSum(int(n / 10))) </em>

If the number is lesser than 0, this recursively sum up the absolute value of the digits (i.e. the positive equivalent). The result is then negated

<em> else: </em>

<em>     return -1 * (abs(n) % 10 + digitSum(int(abs(n) / 10)))</em>

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