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murzikaleks [220]
3 years ago
5

4. What aspect of the initial database planning process would the formula (0 + Pt × 3 + p)/5 be used in?

Computers and Technology
1 answer:
monitta3 years ago
4 0
Time estimation makes the most since in this scenario
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andre [41]

Answer:A lot of people cry when they cut an onion. The trick is not to form an emotional bond.lol

4 0
3 years ago
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Design a class that has an array of floating-point numbers. The constructor should accept an integer argument and dynamically al
attashe74 [19]

Answer:

See explaination for the code

Explanation:

Here is the code

class NumberArray

{

private:

float *aptr; // Pointer to the array

int arraySize; // Holds the array size

float max,min,avg;

public:

NumberArray(int); // Constructor

~NumberArray(); // Destructor

int size() const // Returns the array size

{ return arraySize; }

void storeNumber(float num,int ele);

float retrieveNumber(int ele);

float getHighest();

float getLowest();

float getAverage();

};

//*******************************************************

// Constructor for IntArray class. Sets the size of the *

// array and allocates memory for it. *

//*******************************************************

NumberArray::NumberArray(int s)

{

arraySize = s;

aptr = new float [s];

for (int count = 0; count < arraySize; count++)

*(aptr + count) = 0;

}

//******************************************************

// Destructor for IntArray class. *

//******************************************************

NumberArray::~NumberArray()

{

if (arraySize > 0)

delete [] aptr;

}

void NumberArray::storeNumber(float num,int ele)

{

if(ele<arraySize)

*(aptr+ele)=num;

}

float NumberArray::retrieveNumber(int ele)

{

return *(aptr+ele);

}

float NumberArray::getHighest()

{

float high=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(high<*(aptr+i))

high=*(aptr+i);

return high;

}

float NumberArray::getLowest()

{

float low=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(low>*(aptr+i))

low=*(aptr+i);

return low;

}

float NumberArray:: getAverage()

{

float ag=0;

for(int i=1;i<arraySize;i++)

ag+=*(aptr+i);

ag=ag/arraySize;

return ag;

}

//Header file section

#include <iostream>

using namespace std;

int main()

{

const int SIZE = 10; // Array size

// Define an IntArray with 10 elements.

NumberArray table(SIZE);

//function call to store values

table.storeNumber(1,0);

table.storeNumber(3,1);

table.storeNumber(7,2);

table.storeNumber(2,3);

//display values

cout<<"Highest value:"<<table.getHighest()<<endl;

cout<<"Lowest Value:"<<table.getLowest()<<endl;

cout<<"Average:"<<table.getAverage()<<endl;

///pause system for a while

system("pause");

return 0;

}

6 0
3 years ago
You are attempting to print a document from your workstation to the network printer in your office. The print job failed when yo
Helen [10]

Answer:

An Incident

Explanation:

an incident is an unplanned interruption to a service

6 0
2 years ago
Each column in an access table datasheet represents a ____.
kakasveta [241]
....field while a row represents a record
4 0
3 years ago
4.3 mini programs AP computer science
allochka39001 [22]

1.

name = input("Enter your name: ")

num1 = int(input("Hello "+name+ ", enter an integer: "))

num2 = int(input(name+", enter another integer: "))

try:

   if num1 % num2 == 0:

       print("The first number is divisible by the second number")

   else:

       print("The first number is not divisible by the second number")

except ZeroDivisionError:

   print("The first number is not divisible by the second number")

try:

   if num2 % num1 == 0:

       print("The second number is divisible by the first number")

   else:

       print("The second number is not divisible by the first number")

except ZeroDivisionError:

   print("The second number is not divisible by the first number")

2.

import random, math

num1 = float(input("Enter a small decimal number: "))

num2 = float(input("Enter a large decimal number: "))

r = round(random.uniform(num1, num2), 2)

print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))

I hope this helps!

8 0
3 years ago
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