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Romashka-Z-Leto [24]
3 years ago
7

A pool charges $4 each visit or you can buy a membership. Right and solve an inequality to find how many times a person should u

se a pool so that the membership is less expensive than paying each time. Interpret the solution
Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

<em><u>The inequality is:</u></em>

n > \frac{m}{4}

Membership of the pool will be less expensive until number of visits to the pool is one fourth of the membership amount

<em><u>Solution:</u></em>

Given that,

A pool charges $4 each visit or you can buy a membership

Let "n" be the number of times you visit the pool

Let the membership amount of the pool be "m"

A pool charges $4 each visit

Therefore, cost for "n" visit is: $ 4n

<em><u>The inequality showing that a membership is less expensive than paying each visit to the pool is:</u></em>

4n > m

Divide both sides by "4"

n > \frac{m}{4}

Therefore, membership of the pool will be less expensive until number of visits to the pool is one fourth of the membership amount

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3 years ago
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Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
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Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

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3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

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So, she makes mistake in step 2 as the z terms are not being cancelled.

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