Answer:
6.75 hours
Step-by-step explanation:
162 divided 24
<u>Given</u>:
Given that the regular decagon has sides that are 8 cm long.
We need to determine the area of the regular decagon.
<u>Area of the regular decagon:</u>
The area of the regular decagon can be determined using the formula,

where s is the length of the side and n is the number of sides.
Substituting s = 8 and n = 10, we get;

Simplifying, we get;




Rounding off to the nearest whole number, we get;

Thus, the area of the regular decagon is 642 cm²
Hence, Option B is the correct answer.
Answer:

Step-by-step explanation:
We are given,
Cameron buys 2.45 pounds of apple and 1.65 pounds of pears.
Also, the cost of apples and pears is 'c' dollars per pound.
Thus, the cost of 2.45 pounds of apple is
dollars and the cost of 1.65 pounds of pear is
dollars.
Since, the total cost after using a coupon is $4.12.
So, we get the equation representing the situation is,
Total cost = Total cost of apples + Total cost of pears.
i.e. 
i.e. 
i.e. 
i.e. c = 1 dollar
Hence, the required equation to find c is
.
Hello there ^ _ ^
We know that 36 plates filled 1 box
if we have 1000 plates, how many box it would fill.
All we have to do is divide 1000 by 36 to find the answer.
1000/ 36 = 27.77777 or you can just say 28
I hope this help!
Answer:

Step-by-step explanation:
<u>Binomial Series</u>

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.
Example: 4! = 4 × 3 × 2 × 1
Therefore, the fourth term in the binomial expansion (a + b)⁶ is:





