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3 years ago

6 / 2 (1 + 2) = 9 PLEASE EXPLAIN HOW IT IS 9!!! I followed PEMDAS, and I keep getting 1

Mathematics

1 answer:

Snezhnost [94]3 years ago

4 0

Answer:

Step-by-step explanation:

6 / 2 (1 + 2) = 9

PEMDAS

Parentheses first

1+2 =3

Substitute this in

6 / 2 (3) = 9

Multiplication and Division from left to right

Division first

6/2 =3

Substitute this in for 6/2

3 (3) =9

3*3 =9

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Answer:

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Step-by-step explanation:

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Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

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F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

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$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

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Answer:

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Step-by-step explanation:

Given

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Required

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This is calculated as:

$P(Cheese) = \frac{Cheese}{Total}$

$P(Cheese) = \frac{36}{36+64+20}$

$P(Cheese) = \frac{36}{120}\\$

$P(Cheese) = 0.30$

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