<img src="https://tex.z-dn.net/?f=%20%7B16x%7D%5E%7B2%7D%20%20%20%20%2B%208x%20%2B%201" id="TexFormula1" title=" {16x}^{2} +

timurjin [86]

3 years ago

8x + 1" alt=" {16x}^{2} + 8x + 1" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

${16x}^{2} + 8x + 1 = (4x + 1)(4x + 1) = (4x + 1)^2$

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