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4 years ago

Write down a pair of integers whose sum is –3

Mathematics

2 answers:

inysia [295]4 years ago

7 0

The pair is any numbers, 1 positive and one negative, that add up to -3.
Here is a sample;
(-5, 2)

Vadim26 [7]4 years ago

3 0

Answer:

The pair of two integers such that their sum is -3 are : 6 and -9

Step-by-step explanation:

Integers : This includes the set of all counting numbers and their additive inverses . This set is denoted by Z

Now, we need to find the pair of integers such that their sum is -3

Let x be any integer and the second integer by y

Let x = 6

Now, x + y = -3

⇒ 6 + y = -3

⇒ y = -9

So, The required pair of integers is : 6 and -9

Hence, The pair of two integers such that their sum is -3 are : 6 and -9

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aivan3 [116]

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3 years ago

SOLVE THIS PLS JSJSXHHX

madam [21]

Step-by-step explanation:

y = ax + b

I see already the result (y = x/10 × 1/6), but let's go in formally.

we have multiple function points to use to officially calculate a and b.

1/6 = a×10 + b

2/3 = a×40 + b

5/6 = a×50 + b

1 2/3 = a×100 + b

let's e.g subtract equation 1 from equation 3.

4/6 = a×40 + 0

a = 4/40 / 6 = 4 / 240 = 1/60

1/6 = 10/60 + b

1/6 = 1/6 + b

b = 0

so, the function is

y = x/60

x = 25

y = 25/60 = 5/12 cups

5 0

3 years ago

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean $(\mu)$ = 500 and a standard deviation $(\sigma)$ = 100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = $\dfrac{Y-\mu}{\sigma}$

Z-score = $\dfrac{625-500}{100}$

⇒ Z-score = $\dfrac{125}{100}$

⇒Z-score =1.25

Therefore , the required z-score = 1.25

6 0

3 years ago

What equivalent matches (x - 6 + I)(x - 6 - i)

alex41 [277]

Good evening ,

Answer:

(x - 6 + i)(x - 6 - i) = x² - 12x + 37

Step-by-step explanation:

(x - 6 + i)(x - 6 - i) = [(x - 6) + i]×[(x - 6) - i] = (x-6)² - i² = (x-6)² + 1 = x² - 12x + 37 .

6 0

3 years ago

X-1 1 X+4 + 2x+1 = x-2 2x²-3x-2

kiruha [24]

Answer:

x = 2π3

Step-by-step explanation:

csc(x)csc(x) , x=πx=π

3x+2y+zx+y+z3x+2y+zx+y+z , x=2x=2 , y=3y=3 , z=1z=1

cot(3x)cot(3x) , x=2π3

Hope this helps :)

8 0

3 years ago