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Umnica [9.8K]
3 years ago
14

Can someone please answer these questions?

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Keep in mind that you can gather only like terms. Two terms can be summed/subtracted if they involve the same powers of the same variables.

So, going point by point:

  1. We can subtract the terms, because they both involve the variable b, and we have 3b-7b = (3-7)b = -4b
  2. We can sum the terms, because they all involve the variable a, and we have a+a-5a = (1+1-5)a = -3a
  3. We can't sum this terms: 3 is a pure number, while 3r involves the variable r.
  4. We can only sum the two terms: we have 7t-8t-8 = (7-8)t-8 = -t-8
  5. We can't sum this terms: -20 is a pure number, while -15p involves the variable p.
  6. We can sum the terms, because they all involve the variable g, and we have -g-g-g = (-1-1-1)g = -3g
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Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

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Alvin's age is two times Elga's age. The sum of their ages is 63. What is Elga's age?
lawyer [7]

Answer: Alvin = 42 yrs , Elga = 21 yrs

Step-by-step explanation:

Let Elga's age be x , and Alvin's age be y ,since Alvin is two times Elga's age , then

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y = 2x ............... equation 1

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Solving the resulting linear equations by substitution method.

Substitute equation 1 into equation 2 , we have

x + 2x = 63

3x = 63

x = 63/3

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Therefore : Elga is 21 years old , then Alvin will be 21 x 2, which will be 42

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