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Umnica [9.8K]
3 years ago
14

Can someone please answer these questions?

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Keep in mind that you can gather only like terms. Two terms can be summed/subtracted if they involve the same powers of the same variables.

So, going point by point:

  1. We can subtract the terms, because they both involve the variable b, and we have 3b-7b = (3-7)b = -4b
  2. We can sum the terms, because they all involve the variable a, and we have a+a-5a = (1+1-5)a = -3a
  3. We can't sum this terms: 3 is a pure number, while 3r involves the variable r.
  4. We can only sum the two terms: we have 7t-8t-8 = (7-8)t-8 = -t-8
  5. We can't sum this terms: -20 is a pure number, while -15p involves the variable p.
  6. We can sum the terms, because they all involve the variable g, and we have -g-g-g = (-1-1-1)g = -3g
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false

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2 years ago
A large container holds 5 gallons of water. it begins leaking at a constant rate. After 10 minutes the container has 3 gallons o
dolphi86 [110]
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3 years ago
U guys are mean and never answer my questions, like i paid for no one to answer my question
Sav [38]

Answer:

Step-by-step explanation:

You have no grounds for making a statement like that.  There are a variety of reasons why you might not get immediate answers.  Be patient.

I will do the second part of this question (finding the first three numbers):

a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50

a(3) = 50

a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16

a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6

The procedure for finding a(5), a(6) and a(7) is exactly the same.

3 0
3 years ago
The function f(x)=Acosh(Cx)+Bsinh(Cx). I need help determining the value of constant C>0 when the second derivative f''(x)=25
Rus_ich [418]

Answer:

C = 5.

Step-by-step explanation:

First, you need to remember that:

For the function:

h(x) = Sinh(k*x)

We have:

h'(x) = k*Cosh(k*x)

and for the Cosh function:

g(x) = Cosh(k*x)

g'(x) = k*Cosh(k*x).

Now let's go to our problem:

We have f(x) = A*cosh(C*x) + B*Sinh(C*x)

We want to find the value of C such that:

f''(x) = 25*f(x)

So let's derive f(x):

f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)

and again:

f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)

f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)

And we wanted to get:

f''(x) = 25*f(x) = C^2*f(x)

then:

25 = C^2

√25 = C

And because we know that C > 0, we take the positive solution of the square root, then:

C = 5

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2 years ago
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Answer:

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