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2 years ago

(35 points) Hey please help quickly. :(

Mathematics

2 answers:

UkoKoshka [18]2 years ago

6 0

Answer:here ya go boys

Step-by-step explanation:

Nady [450]2 years ago

4 0

Answer:

No matter where the center of rotation is located on the coordinate plane, each point in the preimage is the same distance from the point of rotation as its corresponding point in the rotated images. This distance is not affected by changing the location of P. Although this investigation covered vertices only, it's clear that any point on a shape or figure will be affected similarly.

Step-by-step explanation:

Thanks to plato FOOOOOLLLLL

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Ishaan is 3 times as old as Christopher and is also 14 years older than Christopher.how old is christopher?

Sedbober [7]

i = 3c

i = c + 14

set both equations equal to each-other, we can

solve for c, we must.

3c = c + 14

subtract c from both sides, we must.

2c = 14

divide both sides by 2, we must.

c = 7

7 years old, Christopher is.

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3 years ago

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Ned took a test with 25 questions. He lost 4 points for each of the 6 questions he got wrong and earned an additional 10 points

lys-0071 [83]

Ned got an overall grade of 86 percent because if each question is 4 points, then 6×4=24 but if he got a bonus 10 points, then you can do 24-10=14 and then you do 100-14 which equals your answer: 86.

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3 years ago

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In the diagram ABC is equal to DEC what is the value of x?

Hatshy [7]

$\begin{gathered} \frac{25}{5}=\frac{18-x}{x} \\ 25x=(18-x)\times5 \\ 25x=90-5x \\ 25x+5x=90-5x+5x \\ 30x=90 \\ \frac{30x}{30}=\frac{90}{30} \\ x=3 \end{gathered}$

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10 months ago

Find an equation of the circle that satisfies the given conditions.

hodyreva [135]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}$

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2 years ago

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Grace [21]

$(x^3)^9=x^{27}$

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3 years ago