All categories

2 years ago

(−2 1/5) × (−5 3/4) as a fraction

Mathematics

2 answers:

svet-max [94.6K]2 years ago

6 0

Answer:

-23 over 10

Step-by-step explanation:

Hope this helped :)

bearhunter [10]2 years ago

5 0

Answer:

253/20

Step-by-step explanation:

(−2 1/5) × (−5 3/4) =

1. change both mixed numerals into fractions.

= -11/5 × (-23/4)

2. Since both numbers are negative, the product is positive. Multiply both numerators together. Multiply both denominators together.

= 253/20

253 is the product of 2 prime numbers, 11 and 23. 20 is the product of 2² and 5. There are no common factors in the numerator and denominator, so this fraction cannot be reduced.

Answer: 253/20

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3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

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Part a)

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$\mu = 74$

and

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Therefore the sampling distribution has a mean of

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The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

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We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

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2 years ago