Answer:
Step-by-step explanation:
Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.
Answer:
Depth = 3 inches
Maximum cross-sectional area = 18 inches²
Step-by-step explanation:
Let 'D' be the depth of the gutter and 'W' be the width of the gutter, the cross-sectional area as function of depth, A(D), is:

The depth for which the derivate of the area function is zero is the depth that yields the maximum cross-sectional area:

The cross-sectional area for D = 3 is:

Use the Pythagorean theorem
H = sqrt (8^2 + 15^2)
H = sqrt(64 + 225)
H = sqrt(289)
H = 17 km
(121.54) x (91-6) =121.54 x 85 =10,330.9
or if these are exponents
(1.18 x 1000) x (9.1 x 0.000001)
(1,180) x (0.0000091)
0.010738