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Nat2105 [25]
3 years ago
7

A 2,000-foot-long fence will be used to enclose a rectangular field that is three times as long as it is wide. What is the lengt

h of the field?
Mathematics
1 answer:
Maslowich3 years ago
6 0
The answer to this question would be: 750ft
In this question, you are given the rectangle perimeter (2,000 ft) and the ratio of rectangle length:width (3:1). The equation of this question should be:

3*rectangle width = 1 *rectangle length 
rectangle width = 1/3 rectangle length

rectangle perimeter = 2,000ft

Then using the rectangle formula, you will be able to find the length. It would be:
rectangle perimeter = 2* (length+width)
2,000ft /2 = 1/3 length + length
1 1/3 length= 1,000ft
length = 1,000ft /4 *3= 750ft
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Line segment MN is graphed in the first and second quadrants of a coordinate plane. The segment is translated 2 units up, then r
Ksju [112]

Answer:

Step-by-step explanation:

Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.

6 0
3 years ago
A rain gutter is made from sheets of aluminum that are 12 inches wide by turning up the edges to form right angles. Determine th
Len [333]

Answer:

Depth = 3 inches

Maximum cross-sectional area = 18 inches²

Step-by-step explanation:

Let 'D' be the depth of the gutter and 'W' be the width of the gutter, the cross-sectional area as function of depth, A(D), is:

2D+W = 12\\W=12-2D\\A =D*W\\A(D)=-2D^2+12D

The depth for which the derivate of the area function is zero is the depth that yields the maximum cross-sectional area:

A'(D)=0=-4D+12\\D=3\ inches

The cross-sectional area for D = 3 is:

A(3)=-2*3^2+12*3\\A(3) = 18\ in^2

6 0
3 years ago
52. Noah’s car has run out of gasoline. He walks 15 km west and then 8 km south looking for a gasoline station. If he is now h k
Stels [109]

Use the Pythagorean theorem

H = sqrt (8^2 + 15^2)

H = sqrt(64 + 225)

H = sqrt(289)

H = 17 km

7 0
3 years ago
Evaluate (1.18×103)⋅(9.1×10−6)
IRINA_888 [86]
(121.54) x (91-6) =121.54 x 85 =10,330.9
or if these are exponents
(1.18 x 1000) x (9.1 x 0.000001)
(1,180) x (0.0000091)
 0.010738
4 0
3 years ago
Please help me answer this question
taurus [48]

Answer:

The answer is21

6 0
2 years ago
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