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kow [346]
4 years ago
12

In which of these systems is the entropy decreasing?

Chemistry
1 answer:
Delicious77 [7]4 years ago
8 0
"A <span>gas condensing to a liquid" is the one system among the following choices given in the question where the entropy is decreasing. The correct option among all the options that are given in the question is the fourth option or option "D". I hope that this is the answer that has come to your desired help.</span>
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Why can color alone be used to identify most minerals?
VladimirAG [237]
<span>Because a lot of minerals have the same color</span>
3 0
3 years ago
The mass of 1.49 of H2 gas at stp
FinnZ [79.3K]

Answer:

Explanation:

I'll assume 1.49 is liters.

All gases occupy 22.4 L for each mole of gas at STP.  This makles a very useful, and important, conversion factor:

(22.4L/mole gas) for all gases at STP.

Therefore 1.49L of H2 would be:

(1.49L H2)/(22.4L/mole gas) = 0.0665 moles

The molar mass of H2 is 2, so:

(0.0665 moles)*(2g/mole) = 0.133 grams to 3 sig figs

3 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
9. Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 0.476 kJ as its temperature changes from 20.5 oC
Shalnov [3]

Answer:

c = 0.528 J/g.°C

Explanation:

Given data:

Mass of titanium = 43.56 g

Heat absorbed = 0.476 KJ  = 476 j

Initial temperature = 20.5°C

Final temperature = 41.2°C

Specific heat capacity = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 41.2°C - 20.5°C

ΔT = 20.7 °C

476 J = 43.56 g × c × 20.7 °C

476 J = 901.692 g.°C × c

c = 476 J / 901.692 g.°C

c = 0.528 J/g.°C  

8 0
3 years ago
If the mass of a material is 76 grams and the volume of the material is 16 cm3, what would the density of the material be? g/cm3
mafiozo [28]
4.8 g/cm3 with sig figs since it's mass/volume you divide 76 grams by 16 cm3
6 0
3 years ago
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