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SIZIF [17.4K]
2 years ago
6

25. What is the molarity of an H2SO4 solution if

Chemistry
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer:

1

Explanation:

hope it helps:)

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Can someone help me with this molar mass problem?[It’s the last one]
quester [9]

Answer:

54.18 \times 10^{23} \ moles in 3 mole of  Al_2(SO_4)_3

Explanation:

It is clear that in the given 1\ mole of Al_2(SO_4)_3 have 3\ ions of SO_4^2^-

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Since 1 ion of anything is equivalent to 6.02\times10^{23} \ moles

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Which is equivalent to 9 \times6.02\times10^{23}=54.18\times10^{23} \ moles

Thus 3 moles of  Al_2(SO_4)_3 gives 54.18\times10^{23} \ moles of  SO_4^2^-.

5 0
3 years ago
Record the volume of the liquid in the graduated cylinder. The volume of the liquid is
mario62 [17]

Answer:

53

Explanation:

5 0
3 years ago
Would precipitation occur when 500 mL of a 0.02M solution of AgNO3 is mixed with 500 mL of a 0.001M solution of NaCl? Show your
Oksanka [162]
We know,
AgNO3 + NaCl ⇒ NaNO3 + AgCl(s)
The moles of Na+ present:
0.5 L * 0.001 mol/L
= 5 x 10⁻⁴ mol
Moles of Ag+ present:
0.5 * 0.02
= 0.01 mol
The limiting reactant is Na
Therefore, the moles of Ag reacted:
5 x 10⁻⁴
AgCl is insoluble in water; therefore, the AgCl formed will precipitate
7 0
2 years ago
Which type of decomposer only breaks down living and dead plant material ​
Sphinxa [80]

well, worms break down dead plants and bacteria can break down animal flesh and plants. Hope this helps :)

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3 years ago
De selectat din poezia ,,O strada cu sentimente" cat mai multe imagini artistice si figuri de stil
Oliga [24]

Answer:

is this english?

Explanation:

7 0
2 years ago
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