In the following redox reaction, the reducing agent is MnO2 (option D). Details about reducing agent can be found below.
<h3>What is a reducing agent?</h3>
A reducing agent in a redox reaction is any substance that reduces, or donates electrons to another, hence, it becomes oxidized.
According to this question, a redox reaction is given as follows: MnO2(s) + 4H+(aq) + 2Cl–(aq) = Mn2+(aq) + 2H2O(l) + Cl2(g)
As shown in the equation, MnO2 is oxidized into Mn2+, therefore, it is the reducing agent.
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Covalent bonds are formed between atoms which have
<span>- unsatisfied valency </span>
<span>- no inert gas electronic configuration </span>
<span>- These are directional bonds </span>
<span>- formed by sharing of electrons </span>
<span>Intermolecular forces </span>
<span>- much weaker than covalent bond </span>
<span>- These are not directional (except Hydrogen bonds) </span>
<span>- These are more electrostatic in nature </span>
<span>- exist between stable molecules </span>
<span>- can be Hydrogen bonding, dipole-dipole and induced dipole-induced dipole </span>
Answer:
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Explanation:
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<span>C7H8
First, determine the number of relative moles of each element we have and the molar masses of the products.
atomic mass of carbon = 12.0107
atomic mass of hydrogen = 1.00794
atomic mass of oxygen = 15.999
Molar mass of CO2 = 12.0107 + 2 * 15.999 = 44.0087
Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488
We have 5.27 mg of CO2, so
5.27 / 44.0087 = 0.119749 milli moles of CO2
And we have 1.23 mg of H2O, so
1.23 / 18.01488 = 0.068277 milli moles of H2O
Since there's 1 carbon atom per CO2 molecule, we have
0.119749 milli moles of carbon.
Since there's 2 hydrogen atoms per H2O molecules, we have
2 * 0.068277 = 0.136554 milli moles of hydrogen atoms.
Now we need to find a simple integer ratio that's close to
0.119749 / 0.136554 = 0.876937
Looking at all fractions n/m where n ranges from 1 to 10 and m ranges from 1 to 10, I find a closest match at 7/8 = 0.875 with an error of only 0.001937, the next closest match has an error over 6 times larger. So let's go with the 7/8 ratio.
The numerator in the ratio was for carbon atoms, and the denominator was for hydrogen. So the empirical formula for toluene is C7H8.</span>
