| Sample Response: Linear relationships can be

Mathematics

1 answer:

IgorLugansk [536]2 years ago

4 0

Answer:

Initial value (y-intercept) of each function.

Rate of change (slope) of each function.

Initial value to compare starting points.

Slope to compare rise or fall. (Answer)

Step-by-step explanation:

Sample Response: Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.

Therefore, I included in the response

Initial value (y-intercept) of each function.

Rate of change (slope) of each function.

Initial value to compare starting points.

Slope to compare rise or fall. (Answer)

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a street light is at the top of a 18 ft tall pole. a woman 6 ft tall walks away from the pole with a speed of 4 ft/sec along a s

shutvik [7]

The most appropriate choice for similarity of triangles will be given by -

Speed of tip of the shadow of woman = 6 ft/s

What are similar triangles?

Two triangles are said to be similar, if the corrosponding angles of the triangles are same and the corrosponding sides of the triangles are in the same ratio.

Here,

The diagram has been attached here

Let the distance of woman from the pole be x ft and the distance of tip of the shadow to the pole be y ft.

Height of street light = 18 ft

Height of woman = 6ft

The two triangles are similar [As height of woman is parallel to the height of pole]

$\frac{y - x}{6}=\frac{y}{18}\\18y - 18x = 6y\\18y - 6y = 18x\\12y = 18x\\y = \frac{18}{12}x\\y = \frac{3}{2}x\\$