It’s rhombuses and kites!
A kite is a quadrilateral with exactly two pairs of adjacent congruent sides. (This definition excludes rhombi. Some textbooks say a kite has at least two pairs of adjacent congruent sides, so a rhombus is a special case of a kite.)
Area covered by the forest in the beginning = 1500km²
Decrease in area each year = 5.8% = 5.8/100 × 1500 = 87km²
Decrease in the area of the forest in <em>t</em> years = 87t
Area of forest now = y
y = 1500 - 87t
K×4-7=k/2/3
4k-7=k×3/2
4k-7=1.5k
4k-7-4k=1.5k-4k
-7=-2.5k
-7/-2.5=-2.5k/-2.5
2.8=k
The first thing we must do for this case is to find the equation of the line.

We have then:

We choose an ordered pair:

Substituting values:
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
Slope of the line:
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5

The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.
Answer:
10 units
Step-by-step explanation:
Given that,
The area is modeled by the equation as follows :

Where
l is the linear dimensions of the frame.
Put A = 100
So,

So, the linear dimension of the frame is equal to 10 units.