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lys-0071 [83]
2 years ago
6

Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 faster than the other. If the two

cyclists are 74 miles apart after 2 hours, what is the rate of each cyclist?
Mathematics
1 answer:
zzz [600]2 years ago
5 0

The rate of the slower cyclist is 16 mph while the rate of the faster cyclist is 21 mph.

<h3>How to calculate the rate of speed?</h3>

let us assume the following;

x = rate of slower cyclist

x + 5 = rate of faster cyclist

We know that formula for distance is;

distance = travel time*rate

Thus;

2x + 2(x + 5) = 74

Since the two cyclists are a distance of 74 miles apart after a time 2 hours. Thus;

2x + 2x + 10 = 74

4x + 10 = 74

4x = 74 - 10

4x = 64

x = 64/4

x = 16

Rate of faster cyclist = 16 + 5 = 21 mph

Read more about Rate of Speed at; brainly.com/question/2681210

#SPJ1

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