When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
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These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
So first divide by 10 to get 32.2 then multiply by the remaining which is 3/10 so 3. 32.2 times 3 is 96.9 round up 97 add to 322 to get 419.
Your welcome
Answer: 10 km in one hour
Step-by-step explanation:
If there are nine hours, and we need to find the distance it will cover in one hour, then we need to divide 90 by 9.
90 ÷ 9 = 10
A train covers 10 km in one hour.
Hope this helps!