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alexira [117]
3 years ago
7

list three different ways to write 5 (with an exponents of 11) as the product of two powers. explain why all three of you expres

sions are equal to 5 with an exponent of 11...
Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0
Ok i got it its 5^1 5^3 5^8 and 5^10 lol yw

balu736 [363]3 years ago
5 0

when multiplying a number to a power, you add the powers.

for example 5^3 x 5^8 = 5^11

you can do the same with 2&9, 4&7, 5&6

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Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

Highway = 155\ miles

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
2 years ago
A certain solution of salt water is 10% salt and weighs 50 pounds., More salt must be added to produce a solution that ls
SpyIntel [72]

what are do you want from me i don't even know my bad

5 0
2 years ago
Please help!! Is it possible to prove that the triangles are congruent by using the AAS Congruence Theorem?
goldenfox [79]

Answer:

no, there is not enough information to use AAS congruence theorem to prove the triangles are congruent

6 0
2 years ago
Suppose 2 /7 of students in your school wore shorts today. How many students would you have to select randomly, on average, in o
Sveta_85 [38]

Answer: 49 students

Step-by-step explanation:

2 /7 of students in a school wore shorts today. The number of students to be selected in order to get 14 students who will wear shorts to school will be:

Let the number of students that will be sampled be y. This will be:

2/7 of y = 14

2/7 × y = 14

2y/7 = 14

Cross Multiply

2y = 7 × 14

2y = 98

y = 98/2

y = 49

49 students will be selected randomly.

8 0
3 years ago
Bradley completed 3/5 of his homework. What percent of his homework does he still need to complete?
Y_Kistochka [10]
1 - 3/5 = 5/5 - 3/5 = 2/5 = 0.4 = 40%
5 0
3 years ago
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