8 so it would be 2/8 plus 3/8
Question:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.
What is the solution set of this problem?
Answer:
Step-by-step explanation:
Given
<em>Represent the number with x</em>
So:
Required
Determine the solution set
Open Both Brackets
Collect Like Terms
Multiply both sides by -1
Hence, the solution set is
Answer:
x^3 - 2x^2 + 9x - 18.
Step-by-step explanation:
The complex roots occur in conjugate pairs so there are 3 roots 2, 3i and -3i.
So we have:
P(x) = (x - 2)(x - 3i)(x + 3i)
= (x - 2)(x^2 - 9i^2)
= (x - 2)(x^2 - 9*-1)
= (x - 2)(x^2 + 9)
= x^3 + 9x - 2x^2 - 18
= x^3 - 2x^2 + 9x - 18.
The right triangle has legs of x and 2.5 where x is the height up the wall that the ladder will reach. The length of the ladder is the hypotenuse of the right triangle.
According to the Pythagorean Theorem, x^2 + 2.5^2 = 12^2
x = 11.736 approx To the nearest tenth that is 11.7.
Answer:
A and D
Step-by-step explanation:
