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Brums [2.3K]
3 years ago
15

Find the size of the final unknown interior angle in a polygon whose other interior angles are:

Mathematics
1 answer:
qaws [65]3 years ago
3 0

Answer:

Step-by-step explanation:(2ñ-4)90

(7×2-4)90

=900°

900-(162+125+148+105+98+115)

900-753

=147°

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1. \: MC  \: is \:  tangent \:  to \:  (B)\Rightarrow \widehat{BCM}=90° \\ 2. \: MC  \: and \: MZ \: are \:  tangent  \: to  \: (B)\Rightarrow MC = MZ\Leftrightarrow 5x - 9 = x + 7\Leftrightarrow x = 4 \\ 3. \: BM =  \sqrt{ {BC}^{2} + {MC}^{2}  }  =  \sqrt{ {5}^{2} +  {12}^{2}  }  = 13 \\ \Rightarrow EM = BM - BE = BM - BC = 13 - 5 = 8 \\ 4. \:  \tan(60°) = \frac{MC}{BC}  =  \frac{13 \sqrt{3}  }{ BC}\Leftrightarrow BC =  \frac{13 \sqrt{3} }{\tan(60°)} =   \frac{13 \sqrt{3} }{ \sqrt{3} }  = 13 \\ 5. \: MC =  \sqrt{ {BM}^{2}  -  {BC}^{2} }  =  \sqrt{ {20}^{2}  -  {12}^{2} }  = 16 \\ 6. \:BZ =  \sqrt{ {BM}^{2}  -  {MZ}^{2} } =  \sqrt{ {25}^{2}  -  {20}^{2} }  = 15 \\ \Rightarrow XE=BX+BE=BZ+BZ=15+15=30

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