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3 years ago

Solve for x.6(x+4)-8x=16

1 answer:

5 0

Answer: x= -4
Have to slove what’s inside the parentheses first so you distribute x & 4 from 6 which gives you 6x + 24 then you subtract 6x & -8x gives you -2x drop down the 24 & begin to do the math

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A chess club plans to sell water to raise $425 and they already have 175, if they sell water bottles for 8$ each, at least how m

alisha [4.7K]

Answer:

32 water bottles

Step-by-step explanation:

8x=425-175

425-175=250

250 is how much more they need.

8x=250

x=31.25

You can't have half of a bottle... so round up to at least 32 water bottles

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2 years ago

48+49+50+51+...112+113

Stels [109]

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Step-by-step explanation:

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3 years ago

A basketball is 11 times heavy as a tennis ball. If a tennis ball weighs 58 gram, what is the weight of a basketball in kilogram

Eva8 [605]

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Step-by-step explanation:

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3 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

6 0

2 years ago

How do you add 1/15 + 1/6?

Brut [27]

you are going to need to find the common name of common denominator 4/1 over 4 plus 1 over 6 equal to look for the commentator of 15 and 6 what goes into 15 and 6 is going to 15 and 6 the common denominator will be actually 12 to 6 only go into 15 2 times cuz I can't get close to 15 than q2 so you have to common denominator now this is going to be both 1/12 + 1/12 is going to be either 2/24 or 2/12

6 0

3 years ago

Read 2 more answers

Solve for x.6(x+4)-8x=16​

Solve for x.6(x+4)-8x=16