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3 years ago

What is this simplified? y+x+y+y+x

Mathematics

1 answer:

Airida [17]3 years ago

4 0

Answer:

$2x + 3y$

Step-by-step explanation:

$y+x+y+y+x \\ =x + x + y + y + y \\ = 2x + 3y$

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I have to use trigonometric identities to solve. But I’m having trouble finding the values of cos A and sin B. Can anyone help m

katrin [286]

let's notice something, angles α and β are both in the I Quadrant, and on the first quadrant the x-coordinate/cosine and y-coordinate/sine are both positive.

$\bf \textit{Sum and Difference Identities} \\\\ cos(\alpha - \beta)= cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(\alpha)=\cfrac{\stackrel{opposite}{15}}{\stackrel{hypotenuse}{17}}\impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}$

$\bf \pm\sqrt{17^2-15^2}=a\implies \pm\sqrt{64}=a\implies \pm 8 = a\implies \stackrel{I~Quadrant}{\boxed{+8=a}} \\\\[-0.35em] ~\dotfill\\\\ cos(\beta)=\cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}$

$\bf \pm\sqrt{5^2-3^2}=b\implies \pm\sqrt{16}=b\implies \pm 4=b\implies \stackrel{\textit{I~Quadrant}}{\boxed{+4=b}} \\\\[-0.35em] ~\dotfill$

$\bf cos(\alpha - \beta)=\stackrel{cos(\alpha)}{\left( \cfrac{8}{17} \right)}\stackrel{cos(\beta)}{\left( \cfrac{3}{5} \right)}+\stackrel{sin(\alpha)}{\left( \cfrac{15}{17} \right)}\stackrel{sin(\beta)}{\left( \cfrac{4}{5} \right)}\implies cos(\alpha - \beta)=\cfrac{24}{85}+\cfrac{60}{85} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill cos(\alpha - \beta)=\cfrac{84}{85}~\hfill$

5 0

3 years ago

Simplify : a–(b–c)+(m+n) x+a + (m – 2) m + (a–k–b) x + (a–b) – (c–d)

Masja [62]

Answer:

The simplified expressions are

1) a - b + c + m + n

2) x + a + m - 2

3) m + a - k - b

4) x + a - b - c + d

Step-by-step explanation:

1) a - (b - c) + (m + n)

To simplify the above expression, we have;

a - (b - c) + (m + n) = a - b - (-c) + m + n = a - b + c + m + n

2) x + a + (m - 2)

To simplify the above expression, we have;

x + a + (m - 2) = x + a + m - 2

3) m + (a - k - b)

To simplify the above expression, we have;

m + (a - k - b) = m + a - k - b

4) x + (a - b) - (c - d) = x + a - b - c -(- d)) = x + a - b - c + d

6 0

3 years ago

Student

Bess [88]

Step-by-step explanation:

Is that the whole question or can you give me more information?

6 0

3 years ago

The perimeter of a rectangular campsite is 64 cm and its area is 207 cm. Find the length and the breadth of the rectangle.

AlladinOne [14]

Perimeter Formula:
$2l + 2b = 64$

Area Formula:
$l \times b = 207$
Set perimeter Formula equal to b:
$2l + 2b = 64 \\ 2(l + b) = 64 \\ l+ b = 32 \\ b = 32 - l$
Plug formula for be we just made above into the area Formula:
$(32 - l) \times l = 207$

Solve for L (you'll have to use quadratic formula) then plug that back into the area Equation and solve for b.

Here's a link to where the problem has been explained before (they go into more detail than me).

https://brainly.ph/question/468631

lmk if you need any more help

6 0

3 years ago

Read 2 more answers

I WILL MAKE YOU THE REAL BRAINLIEST

Y_Kistochka [10]

No such thing ,But what you can do is is go on Cymath and it will help you solve it

4 0

3 years ago